Question

Name: J# Q1 - 20 pts) Consider the status of a TCP connection at the source and destination as shown in the Figure and Table below. Let the Congestion Window size be CW bytes and Maximum Receiver Buffer Size be RB bytes. What would be the Effective Window Size (the amount of data that can be sent) by the source considering: Max. Receive Buffer= RB bytes Destination Process Source Process Notation Description Last Byte Acknowledged Last Byte Sent Last Byte Read Last Byte Received J#; Name: nce Number RB byes bytes A | B C 1 р 7126 | 11528 | 4094 | 9504 т со | 11597 | 222 16

Answer 1

Congestion Window # limits amount of dało the TOP can send into the network, before receiving an Ack Receiver window = the amount of data that the destination side ean receive max. Receive Buffete - RB bytes clutination_Pцоtела. — _3 още _Оде3, Soing Bust max. Receiver Buffer size CW - Congestion Window RW 2 Receiver window s w C Receiver window) - RB - I last Byte Received - last Byte Read 1 - RW 22216 -[ 95041- 40941 ADA M = Ba216 - 5410 24 RW:= 16806 → Windou) Sigeile minimum (RWCW) o minimum (16806, 11597) T window Qize = 115971 3 11.995 kB

- Size of unacknowledged data = [tast byte Bent - tast byte acknowledged] de = 11528 - 712 Way! Jaige ol anacknowledged data = 4404_) bytes 24: 300 KB ii 4.3 kB is not acknowledged till now. so. [effective window werent active 1 LYSize - II. » window size di L Current active window dige l i 1 Window size - Dize of unacknowledged data. Cwerent active window dize = 11.325 KB - 4,300 RB !!! wide 4.025 KB. Il Ellective Window Size = 7,025 KB