Question

A chemist determines by measurements that 0.0200 moles of fluorine gas participate in a chemical reaction. Calculate the mass of fluorine gas that participates. Round your answer to 3 significant digits. 09 X 5 ?

Answer 1

molecular weight of fluorine gas (F2) - 2x atomic weight of - 2x 18.998 Ilmole = 37.996 g/mole E using mole concept we know Number = weight of atom) molecule (ing). of moles = weight of atom/molecul atomic / molecular weight Colmole Given Numaber of moles of Fogas - 0.0200" mass of u gas = Number of moles x molecular weight = 0.0200(mole) x 37.996 & mole = 0.75992 om SR 55 0.760 gm - 0.760gm gas participate in the reaction