Homework Answers
Work done to stretch the spring a distance x is,
Work done,W = 0.5kx^2
k = W/(0.5x^2) = 18J/(0.5*0.9^2)m^2 = 44.45 N.m
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Caloulate the work required to stretch the following springs 1.5 m from their equilibrium positions. Assume Hooke's law is obeyed a. A spring that required 80 J of work to be stretched 0.2 m from its equilibrium position. b.A spring that required a force of 250 N to be stretched 0.4 m from its equibrium position a. Set up the integral that gives the work done in strotching the spring 1.5 m from its equilibrium position. Use increasing Imits of...
A spring with a force constant k = 2.2x10^2 N/m is stretched by
a person. The person pulls on the spring with a final applied force
of F_app = 44 N at equilibrium (no motion). How much work was done
by the person in the process?
A spring with a force constant k = 2.2x10^2 N/m is stretched by a person. The person pulls on the spring with a final applied force of F_app = 44 N at equilibrium (no...
A spring on a horizontal surface can be stretched and held 0.7 m from its equilibrium position with a force of 70 N. a. How much work is done in stretching the spring 5.5 m from its equilibrium position? b. How much work is done in compressing the spring 1.5 m from its equilibrium position? a. Set up the integral that gives the work done in stretching the spring 5.5 m from its equilibrium position. Use increasing limits of integration....
A spring on a horizontal surface can be stretched and held 0.6 m from its equilibrium position with a force of 66 N. a. How much work is done in stretching the spring 5.5 m from its equilibrium position? b. How much work is done in compressing the spring 4.5 m from its equilibrium position? a. Set up the integral that gives the work done in stretching the spring 5.5 m from its equilibrium position. Use increasing limits of integration...
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