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Need help doing this problem as well as drawing a free body diagram.
7)--A billiard ball traveling at 20.0 m/s collides with an identical ball at rest. After the collision, the first ball moves
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Answer #1

considering momentum along vertical

initial vertcial momentum = final vertical momentum

0 = v1 sin 40 - v2 sin x

v2 sin x = 7.7 sin 40

v2 sin x = 4.95 ....(i)

considering momentum along horizontal

20= 7.7 cos 40 + v2 cos x

v2 cos x = 14.1 ...(ii)

squaring and adding (i) and (ii)

( v2 sin x)^2 + ( v2 cos x)^2 = 4.95^2 + 14.1^2

v2 = 14.945 m/s

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comment in case any doubt, will reply for sure...goodluck

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