Question

11) An 80% free throw shooter takes 4 free throws. Find the probability that the shooter a) makes all 4 shots b) misses all 4 shots c) makes at least 1 shot

Answer 1

It is given that the probability of success is 80%.

n=4

The required probability can be calculated using the binomial distribution as:

a) The required probability is:

P(X=4) =4C4 *(0.80)^4 *(1-0.80)^(4-4)=0.4096

b) The required probability is:

P(X=0) =4C0 *(0.80)^0 *(1-0.80)^(4-0)

=0.0016

c) The required probabi;ity is:

P(At least one) =P(X=0)+P(X=1)

=4C1 * (0.80)^1 *(1-0.80)^3

=0.0016+0.0256

=0.0272

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