Question

maxterms minterms 0 1 0 1 0 1 10 101

1- Write the unsimplified POS Boolean equation for F from the Truth Table.

F =

2- Write the unsimplified SOP Boolean equation for F' from the Truth Table.

F' =

3- Using only DeMorgan’s Theorem (show steps) and the unsimplified POS Boolean equation,

find.

Answer 1

pole Given Thange P8 ser change oooooo O B c ol El Maxterms! Il minemy 0 0 0 0 0 0 0 0 1 0 0 0 100 - - - - Oo---0-0-00-0 do. com - ---O0O-o-o- -o-oo .-Ilio! O 1 Osim +SA 11 00 1 1 0 1 Note :) Maxterms are the elements present when the output f has zero o 0 ii) minterms are the elements present when the output r is 6. ). 10 unsimplified pos off : 2016 iso F - AM 10, 1, 2, 6, 8, 10, 11, 13) = (A&B + C +D) (A + B + C + D) (A+B + C +D) (A+B+C +D) (A+B+C+D) (A +84770 (A+B+C + D) (A+B+C+D) 172

Subject:............. xati.. ..... ») Unsimplified Sop Boolean equation is E = smco, 1, 2, 6, 8, 10, 11, 13) - A B C D + ABCD + Ā B CD & A B C D + ABED & ABCD + ABCD + ABER 3) Simplified pos of £ using DeMorgan's Slep) - (A+B+c+D) CA+B+C+D) (A+B+7 +D) (A + B + C + D Ã + B + C+D) CAB + C +D) CÃ +B + C +D) CÃ + B +C+0) Sepz (CA+b+c) +D) (+8+1) ++)) ((n+E+D) + ) (CA+2+0) 4 @)) (16+ 8 + 0) +c) (+B+B) (C+8+€3+0) (746+C)+)) ( 5+8+ci) Alp: Mote A.A=A B+B = 1 ; A•A' =0 (A+B) (A + B) = A'A + B Bt. A B - Ato+ ALB+B) Formus + AB = A +O+ACI) FATA -

(A+B+C) f = (A+B+C) (Ate+D) A + B +D) (A + B to că + B+CD) ((A+B+D) + c)(64*13) = A + B + c) (A+E+D) (A + B + c) (A + B + cto) (A+B+D) (A + B+ D)) (A+B+C) (A+C+D) CA+Btc) (A + Btc to) (CCB +D)+A) ({B+D+A)) = (A+B+C) CATC+D) (A+B+E) (A+B+C+D) (B+D]