Question

1. How many moles of electrons are represented by a total charge of 1.0 C? The charge on A) 6.2 x 10 mol B) 1.6 x 10-19 mol C) 3.5 x 105 mol D) 1.0 x 10 mol 2. The charge on an electron is 1.602 x 10"9 C. How many electrons flow when 55 pJ of an electron is 1.602 x 10-19 C. electrical energy passes through a voltage of 9 V? A) 3.4 x 10 B) 3.8 x 10' C) 3.6 x 10° D) 3.1 x 10 3. If a current of 2.6 mA flows for a total of 2.00 hours, what total quantity of charge flows? A) 0.31 C B) 19 C C) 0.053 C D) 9.3C takes place. A) reduction B) electrolysis C) oxidation D) current 4. The cathode of an electrochemical cell is where 5. Which of the following move towards the anode during the operation of an ggl ce112

#2

Answer 1

Q = E / V

where V is the voltage

E is the energy

Q is the charge

Q = 55x10^-12 / 9

Q = 6.11x10^-12 C

If charge carried per electron is 1.602x10^-19 C

the the number of electrons that carry a charge of 6.11x10^-12 C will be 6.11x10^-12 / 1.602x10^-19

number of electrons =3.8x10⁷ electorns