Question

calculate the vapour pressure of this solution at 29.8 degree celsius/ you may assume that the solution is so dilute that its density is 1.00 gm cm^-3 Pa

M Correct! A protein has a molar mass of 169000 g mol-1. An aqueous solution of this protein has an osmotic pressure of 0.294 kPa at 29.8 °C. Calculate the concentration of the protein (in g L1) in this solution. 19.72 g L. the tolerance is +/-2% SHOW ANSWER SHOW HINT LINK 1O ILXI Attempts: 1 of 3 used M Correct! Calculate the vapour pressure of pure water at 29.8 °C. (The vapour pressure of pure water can be estimated from pvan = 0.0074T3 - 0.0234T? + 6.2049T + 58.464, where Tis in °C and pvan is in Pa.) 418.42 Pa. the tolerance is +/-2% SIJOW INI SHOW ANSWLR LINK TO TCXT Attempts: 1 of 3 used Calculate the vapour pressure of this solution at 29.8 °C. You may assume that the solution is so dilute that its density is 1.00 g cm3. Pa. the tolerance is +/-2%

Answer 1

Conc. of protein 19.72 g/L = Volume x density Mass of so lution (density = 1 almL) = Volume %3D 1000 g IL of solution So, mass ニ 19.72 g mass of protein = 480.28 9 = (1o00 -19.72) a of water > Mass 980.28 E Mole frachon of waten ( XH,0) 18.0 a/mol 980.28g 19.72 8 18.0 9 169000 8 mol Mol 0.999 law, Using Raoult's Х н,о %3D vapor preuuu of solution (p) = f'40 x X H,o = 418.42 Pa x 0.999 418.419 Pa