Question

Can somebody help me please and please show your work

At 15.0 degree C, an aqueous solution that is 35.0 % sucrose (C_12H_22O_11) by mass has a density of 1.145 g/mL. What is the molality of the solution? What is the molarity of the solution? What is the mole fraction of sucrose in the solution?

Answer 1

a) Mass per cent of C12H,011 solution-35.0% 35.0% (m/m) C12H22011 contains 35.0 g of C12H22O11 solute per 100 g of solution 22115 1 mol CHOu 342 g No of moles of nHn , solute 35.0 g x 2211 0.102 mol CHnO, Mass of C ,H,,0u solution = 1 00 g Denisty of CnHsolution-1.145 g/mL 22 11 Volume of C1H201 solution 100 g x-8 m 87.3 mL -0.0873 L 1.145 g Molarity of CpH2O-no of moles of Ch Ha O volume of soluti on 0.102 mol Co. 12-2211 0.0873 L = 1.17 mol/L 0.146 M b) No of moles of 2H22O1 solute0.102 mol nH2011 Mass of solvent -mass of solution -mass of 12H2u solute 100 g-35g 75g0.075 kg Molality of soluti on - no of moles of C1H20n solute 0.075 kg c) No of moles of CvH2201 solute 0.102 mol C12HO1 No of moles of water(H,).750gx 1mdl Ho mass of solvent in kg 0.102 mol-1.36molkg 1.36 m No of moles of water H,O = 4.16 mol H2O 18.02 g 0.102 mol 0.102 mol + 4.16 mol 0.0239