Question

Vcc= 15 V Rc 2 kO R1 10 kO Vo C1 R2=5 kQ Vs RE= 2 kQ Figure 1.1 [Rajah 1.1)

Answer 1

Operating Region of Bipolar function Transistor (BJT): - we can consider the nap traitors In case of operate in Amplification mode implies E - B function is forward Biased (FB) and CB function reverse biased (RB) implies such that V_cE > 0. 2 v to and T c both are greater from zero implies V_BE greaterthanorequalto v_(ON) Typically implies V_B (ON) = 0. 7 Volt For Saturation Node - when the E - B function and C - B function both are forward based then transistor is operated in salutation mode - for this case: - V_cE = V_ce (at) = 0. 2 v Both I_B and I_c are greater then zero V_BE greaterthanorequalto V_BT (or) In this mode - transitory is behaves as closed switcher For Cut off Region: - when both E - B function and collector base function are converse biased then transistor is said to operate in cut off Region implies In this region it as open swathe I_B