How would you write the three dissociation equations for a buffering compound (H2B^2+) given that pka1...
How would you write the three dissociation equations for a buffering compound (H2B^2+) given that pka1 = 7.79, pka2 = 9.79, and pka3 = 9.92? This is the only information provided.
Homework Answers
have this equations in water
dissolved that are basic .
![H2B =H+ +H,B Ki = pK1 = -log K1 Hº] H,B (H,B [H+] · (HB-2) [H,B) H]. B-31 -2 H,B + HB K2 pK2 = -log K2 IB-2 =H+ +B-3 K3 pK3](http://img.homeworklib.com/questions/5686c3b0-cd47-11ea-b13d-231187dc7c5c.png?x-oss-process=image/resize,w_560)
compare it
Hope it clears
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