Confidence Interval formula
Mean ± Margin of error
Lower Limit = Mean - Margin of Error
Lower Limit = 28 - 2.2 = 25.8
Upper Limit = Mean + Margin of Error
Upper Limit = 28 + 2.2 = 30.2
99% confidence interval is ( 25.8 , 30.2 ).
The mean number of hours of part-time work per week for a sample of 526 college...
The mean number of hours of study time per week for a sample of 559 students is 23. If the margin of error for the population mean with a 99% confidence interval is 1.7, construct a 99% confidence interval for the mean number of hours of study time per week for all students
The main number of hours of part-time work per week for a sample of 133 high school students is 27 is the margin of error for the population mean with 80 for 98% confidence interval of 2.4 constructive 98% confidence interval for the main number of hours apart time work per week for students
The mean number of hours of study time per week for a sample of 524 high-school students is 27. If the margin of error for the population mean with a 98% confidence interval is 1.7, construct a 98% confidence interval for the mean number of hours of study time per week for all high-school students. Lower endpoint? upper endpoint?
The mean amount of money spent on lunch per week for a sample of 75 students is $42. If the margin of error for the population mean with a 99% confidence interval is 2.10, construct a 99% confidence interval for the mean amount of money spent on lunch per week for all students.
1. To determine the average number of hours spent studying by college students per week, a sample of 39 students was randomly selected, and found to spend an average of 17.1 hours per week, with a standard deviation of 4.3 hours. Find the 90% confidence interval for the mean number of hours spent studying per week by all college students. What is the upper and lower bound? 2. If I asked a random student how many hours they study per...
A random sample of community college students was asked the number of hours they sleep on a typical week-night during a given academic term. The sample data are as follows: 8 6 4 5 3 7 S 4 3 4 4 5 6 8 7 7 7 3 3 4 What is the 90% confidence interval estimate for the true mean amount of sleep time per night spent by community college students during a academic term? a) The data give...
The University College is interested in the average number of hours per week that freshmen spend going to parties. They took a random sample of 300 freshmen and calculated a mean of 6 hours a week going to parties and a 95% confidence interval for the population mean to be 4 to 8 hours a week. Based on this information, what was their standard error of the mean?
Suppose the average number of hours full-time college students work per week is 25 with a standard deviation of 6 hours.. Random samples of 40 full time students are drawn. Find the mean and the standard deviation of the sample mean
3. In a recent study of 100 eighth graders, the mean number of hours per week that they watched television was 22.6. Assume the population standard deviation, o, is 5.2 hours. (Section 6.1) Construct a 90% confidence interval for the population mean number of hours that eighth graders watch television • Margin of error, E..8554 Confidence interval:al: 74<us 23.46 If the population standard deviation was reduced by 50% to 2.6 and the level of confidence remained at 90%, what would...
"The National Dung Beetle Association reported that the mean number of hours spent per week on breeding and training by dung beetle coaches (called clingers) during the season was 45 hours. You are not sure their claim is correct, so you gather a random sample of data from 40 clingers showing the sample mean to be 42 hours with a standard deviation of 7.2 hours. Use the sample data to construct a 99% confidence interval for the population mean." In...