Question

Please use MATLAB

ME2543 Simulation Methods > Assignment 10: Interpolation and Curve Fitting > Problem 1 O solutions submitted (max: Unlimited) Given the following data: Temperature, T[°C] 100 150 200 250 300 400 500 Energy, u (KJ/kg] 2506.7 2582.8 2658.1 2733.7 2810.4 2967.9 3131.6 • Plot u versus T • What is the interpolated value for u=2680.78 KJ/kg • Test out the spline interpolation and plot the new data generated Script C Reset MATLAB Documentatic 1 % 'interp_u' has to be used to memorize the interpolated value for u=2680.78 kJ/kg interp_u =

Answer 1

Matlab Code:

clc
clear all
T = [100 150 200 250 300 400 500];
u = [2506.7 2582.8 2658.1 2733.7 2810.4 2967.9 3131.6];
ua = 2680.78;
%simple interpolation
interp_u = interp1(u,T,ua)
%spline interpolation
figure
Tq = 100:10:500;
u2 = interp1(T,u,Tq,'spline');
plot(Tq,u2,':.');
xlabel('temperature')
title('Spline Interpolation');

clc clear all T = [100 150 200 250 300 400 500]; u = [2506.7 2582.8 2658.1 2733.7 2810.4 2967.9 3131.6); ua = 2680.78; simple interpolation interp_u = interpl (u, T, ua) spline interpolation figure Tq = 100:10:500; u2 = interpl (T, u, Tg, 'spline'); plot (Tg, u2,':.'); xlabel('temperature') title ('Spline Interpolation');

Output:

interp_u =

215.0000

>>

Command Window interp_u = 215.0000 fx >>|

Plot:

- 0 x Figure 1 Eile Edit View 9803 B Insert Tools Window Desktop A Help O E O Spline Interpolation 3200 3100 3000 2900 2800 2700 2600 250960 150 200 250 300 350 400 450 500 temperature