A light ray propagates in Material 1 with index of refraction n = 1.17, strikes an...

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Question

$A light ray propagates in Material 1 with index of refraction n = 1.17, strikes an interface, then passes into Material 2 wit$

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Answer 1

Answer #1

Solution)

Given,

Index of refraction, n1=1.17

Index of refraction, n2=1.49

Angle of incidence, theta1=21.3°

We know, from Snell's Law

N1*sintheta1= n2*sintheta2

Substitute values

1.17*sin(21.3)=1.49*sin(theta2)

So, theta2= 16.57° (Ans)

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Answer 2

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