Question

Write the method: public static String doubleVowels(String x). This method takes a String x and returns a new String y which is identical to x except wherever there is a vowel in x, there will be two of that same vowel in the returned String y. The original String x will contain only lower case letters.

For example, doubleVowels("easy") should return the String "eeaasy".
Another example: doubleVowels("abootstrap") should return the String "aabooootstraap".
Another example: doubleVowels("gggrrrhh") should return the String "gggrrrhh".

public static String doubleValue(String x) {

Answer 1

The solution for the above question is given below with the screenshot of output.
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I have kept the logic simple and output as per the question.

If there is anything else do let me know in comments

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-------------------------- CODE TO COPY ------------------------------------------

import java.util.Scanner;

class Main {

  // double vowels in string
  public static String doubleVowels(String x) {

    int i;
    int size = x.length(); // find length of string
    String y = "\0";

    // loop for find vowels in string
    for( i =0; i < size; i++) {
      if(x.charAt(i) == 'a' || x.charAt(i) == 'e' || x.charAt(i) == 'i' || x.charAt(i) == 'o' || x.charAt(i) == 'u') {  // if string contain vowels
        y = y + x.charAt(i) + x.charAt(i);
      }
      else { // string contain consonents
        y = y +  x.charAt(i);
      }
    }
    
    return y;
  }

  public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);
    
    // input string
    System.out.print("Enter String : ");

    String y = sc.nextLine();

    // change string into lower case
    y = y.toLowerCase();

    y =  doubleVowels(y);

   System.out.println("Final String : " +y);

  }
}

Output : -----------------------------------------------------------------