Question

perpendicular to the page, taking a 11.0 om and b 23.0 cm. (Indicate the direction with the sign of your Find the net torque on the wheel in the figure below about the de through answer. Assume that the positive direction is counterclockwise)

Answer 1

Fi=ION . Ti = # bx Fi Tz = b x'F2 Iz = 12Nt to & ax F3 F2=9N CL Here Tz do mot effcted by given Angle (304) because Fq is berpendicular Tmet = Ti + Tz to immer surface + Tl of sphere. =-Ti-Tz. + Tz Here -ve ligm Shows - Clock wise direction tve sign Shows - Counter clock wire diren Tmer =-16 X F1 ) - 16 X F2). + ( 9 X F3 ) - =-(17 x 10) – (1989) + (5X12) =-170 -153 +60 Tmet =-263 Nom lave sign shows that - Torque in clock wise.

7 = 6: 509 . S T=&F simo T= - liming simo) Simgó =-l mg fim (6.5°) & Imgsm mgsimo in ingcoso 1-2 x 2.6x9.8 x:1132 mg - S.4688 N- 7 b) It depend on simo then magnitude of torque it is o increase increase