Question

A proton enters a uniform magnetic field and follows trajectory B. Adeuteron (same charge and twice the mass) enters the magnetic field in the same way and with the same velocity as the proton. Which of the following is the right trajectory for the deuteron? CITIXYXXX XX E XXX 107 PM AZ OO

Answer 1

For a charged particle of charge q, mass m, and velocity v

If it enters a magnetic field of intensity B, the radius,r, that it traces can be given by

$r=\frac{mv}{qB}$

for proton, the equation becomes

$r_{p}=\frac{m_{p}v_{_{p}}}{q_{p}B}$

for deuteron this equation becomes

$r_{d}=\frac{m_{d}v_{_{d}}}{q_{d}B}$

but md=2mp (given)

and qd=qp (given)

and vd=vp (given)

so, rd becomes

$r_{d}=\frac{2m_{p}v_{_{p}}}{q_{p}B}$

or

So, the correct answer will be C since the charge is same so direction will be same.

part 2

the correct option is C

any change is kinetic energy of the particle will be caused by electric field