Question

The thermochemical equation for the combustion of acetylene gas, C2H2(g), is 2CH2(g) + 502(g) – 4C02(g) + 2H2O(1) AH = -2599.
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Answer #1

Given:

ΔHo rxn = -2599.3 KJ/mol

From thermodynamics table:

Hof(O2(g)) = 0.0 KJ/mol

Hof(CO2(g)) = -393.509 KJ/mol

Hof(H2O(l)) = -285.83 KJ/mol

Balanced chemical equation is:

2 C2H2(g) + 5 O2(g) ---> 4 CO2(g) + 2 H2O(l)

ΔHo rxn = 4*Hof(CO2(g)) + 2*Hof(H2O(l)) - 2*Hof( C2H2(g)) - 5*Hof(O2(g))

-2599.3 = 4*(-393.509) + 2*(-285.83) - 2*Hof(C2H2(g)) - 5*(0.0)

Hof(C2H2(g)) = 226.802 KJ/mol

Answer: 226.80 KJ/mol

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