Question

Question 4 (1 point) Do you predict 52- or Ca2+ to have a smaller ionic radius? Why? Ca2+ is smaller because it has only two valence electrons whereas S2- has six. OCa2+ is smaller because its nucleus has a larger positive charge which exerts a stronger force than the nucleus of S2- on the same number of electrons. Os2- is smaller because it contains fewer electrons than Ca2+ and therefore has a smaller electron cloud. OS2- is smaller because it has a less massive nucleus than Ca2+ and therefore a smaller radius. O s2 is smaller because it is higher up and farther right on the periodic table than Ca2+,

Answer 1

Question 4 Answer =) @azt is smaller becouse it's orucleus has a largez positive charge which exerts a stronger force than the nucleus at s2-on the same number of electrons. Explanation = Ca (20) = 15², 25², 206, 35², 398, 45² bet we have cart that means 2 electron's less than parent atom hence configuration becomes cat () = 15², 25², 286, 38², 386 for As the electronic configuration is - S(16) 1s? 28², 286, 382, 384 but we 52- hence configuration becomes 82 - is? 25², 286, 35², 3p6 (2 electrons added from electronic configuration we predict that ca2+ and 2- aze isoelectronic species but, in ca? e's numbe? decɛeases and peotons (on are more (ca?t es ace 18 and protons are 2o) grearez attraction between electrons and peoton de size. 1 While in case of s²- no. of electrons increase but not peotons. Cie. in s? no. of electrons 18 and no.ot pectons 16 hence in this case net repulsion of electrons will outweight the nuclear charge and ion will expand in size.