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A 20μF capacitor has previously charged up to contain a total charge of Q=100μC on it....

A 20μF capacitor has previously charged up to contain a total charge of Q=100μC on it. The capacitor is then discharged by connecting it directly across a 100−kΩ resistor. At what point in time after the resistor is connected will the capacitor have 13.5μC of charge remaining on it?

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Answer #1

time to discharge, @= né tlRC - 13.5=100 ê t/600x10² x 20 x1067 & t= 4.005s t = 4 second

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