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In the above figure, vectors P and Q lie in the zy plane. It is also known that 0 = 40°, P = 13 and 0 = 13. Find P x Q. P x =

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goy Given udala magmilude of vectore P (TPU) = 13 magunitude of vector op! (1 ml) = 13 angle 0 - 40° Now wrous product x 9 -where l a magnitude of vectos p 1ộl = magnitude of vecbox B = angle between the vectoru when vector . are caligned tail to taje im 2 direction and unit vecose along z direction is la pxg: lpl IQ) din ß (-k) [(-ve) because - ve Zidirection } = (13)(1

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