(a). Molecular area of hexachlorobenzene = 203 Ao2
For hexachlorobenzene -
a1 = 3.29
a2 = - 0.0422
a3 = - 0.0103
Tm for pure hexachlorobenzene = 231 oC
log C = a1 + a2*Am + a3*Tm
= 3.29 - 0.0422 * 203 - 0.0103 * 231
= 3.29 - 8.566 - 2.3793
= - 7.6553
C = 10^-7.6553
= 2.211 x 10-8 mol/L
calculate aqueous solubility of hexachlorobenzene in water using a) molecular area 203 angstrom b) molecular volume...
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