Probability calculation from z normal distribution table.

According to recent surveys, 60% of households have personal computers. If a random sample of 185...
According to recent surveys, 60% of households have personal computers. If a random sample of 180 households is selected, what is the probability that more than 60 but fewer than 100 have personal computers?
According to a recent survey 60% of households have personal computers. If a random sample of 180 households is selected, what is the probability that fewer than 100 have a personal computer. Approximate Binomial by Normal distribution
How many computers? In a simple random sample of 185 households, the sample mean number of personal computer ls was 1.64. assume the population of the standard deviation is 0.47 a) construct a 99.9% confidence interval for the mean number of personal computers. round the answer to at least two decimal places. a 99.9% confidence interval for the mean number of personal computers is ---< mean <----- 2) In a sample of 75 clamps, the mean step to complete this...
in a simple random sample of 190 households, the sample mean number of personal computers was 2.78. assume the population standard deviation is 0.41. a) a 99.8% confidence interval for the mean number of personal computers is ----< mean <----- 2) a simple random sample of eight college freshman were asked about how many hours of sleep they typically got per night. the results were 7.5, 8, 6.5, 24, 8.5, 6.5, 7, 7.5 a) the data contains an outlier that...
1. According to the U.S. Department of Commerce, 30% of Arkansas households had a computer in 2002. If 285 Arkansas households are selected at random, find the following probabilities: (Please show all necessary justifications.) a.The exact probability that 70 or fewer have a computer b. The probability that 70 or fewer have a computer using the normal approximation. c. The probability that 70 or fewer have a computer using the normal approximation with the continuity correction. 2. The probability that a...
How many computers? In a simple random sample of 150 households, the sample mean number of personal computers was 2.91. Assume the population standard deviation is a =0.57. 5 alo Part: 0 / 4 Part 1 of 4 (a) Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places An 80% confidence interval for the mean number of personal computers is <<
According to the Consumer Electronics Manufacturers Association, 10% of all U.S. households have a fax machine and 52% have a personal computer. Suppose 91% of all U.S. households having a fax machine also have a personal computer. What is the probability that a randomly selected U.S. household has a fax machine and a personal computer? What is the probability that a randomly selected U.S. household has a fax machine or a personal computer? What is the probability that a randomly...
according to a government commission, 70% of all nations households
have VCRs. In a random sample of 15 households, what is the
probability that at least 13 have VCRs? Round to four decimal
places
According to a government co have VCRs? Round to four de O O 0 O 0.1268 0.7000 0.5000 0.8732
A recent poll indicated that about 75% of U.S. households had access to a high-speed Internet connection. B. If 10 households are selected randomly, what is the probability that exactly 6 have high-speed access? The probability that exactly 6 households have high-speed access is Answer _____. (Type an integer or decimal. Round to three decimal places as needed.) C. If 10 households are selected randomly, what is the probability that 6 or fewer have high-speed access? The probability that 7...
11. Pet Ownership A recent random survey of households found that 14 out of 50 householders had a cat and 21 out of 60 householders had a dog. At a = 0.05, test the claim that fewer household owners have cats than household owners who have dogs as pets.