Question

Need Help on 1-6 please

1. Mercury ions exit as the mercurous dimer Hg22+ and Hgt. If Hg22+ is in contact with liquid mercury, Hg (1), the following equilibrium is established: Hgt(aq) → Hg22+(aq) + Hg(1) K= 2.24x10-5 If a 0.15 M solution of Hgt is put in contact with liquid mercury, what will be the resulting equilibrium concentration of Hg22+? Show work a. 3.36 x 10-6 M b. 1.83 x 10-3 M c. 1.14 x 10-2 M d. 0.83 x 10-4 M 2. The sulfide ion, S., reacts with water as a weak base: S2 (aq) + H2O + SH (aq) + OH-(aq) with an equilibrium constant of 5.0x10-5. If sodium sulfide were dissolved in water to make a solution of 0.50 M, what would be the resulting concentration of OH”? a. 2.5x10-5 M b. 5.0x10-3M c. 0.50 M d. 5.0x10-5M 3. Kb implies the following reaction (where B is a weak base): a. B + OH BOH b. B+H+ BH+ c. B + H20 BH+ + OH- d. BH+ H+ +B 4. Which best describes an aqueous solution of phosphoric acid? a. Dissociates completely b. Doesn't dissociate at all c. 45% dissociates; 55% stays as whole molecules d. Partially dissociates, mainly stays as whole molecules 5. In the following reaction, which is the acid reactant and its conjugate base product? CH3C00- + NH4+ CH3COOH + NH3 a. CH3COO- and CH3COOH b. NH4+ and CH3COOH c. CH3COO- and NH3 d. NH4+ and NH3 What is the pH of a 0.010 M solution of hydrocyanic acid, HCN,? Ka of hydrocyanic acid is 6.2 x 10-10 a. 5.6 b. 4.5 c. -5.6 d. 8.4

Answer 1

Hope you will like my answer:)

o Ginen — reaction is Hg (02.) = unbalanud , ubon balancing Hg2+107) + ng (1) K = 9.24x10 to Change: - Equilibrium: (0.5-) a Given initial concentration of rgt = 0.15 M as equilibrium some of higt must have formed hat due to which decrease in concentration of Hgt will be a. eeft equilibriem, by law of mass action ka [Hg2+] well Putning values in above equalson, 9,24 X10-5 a 0.15- •: .24 x 10-5 is very small 0.15- & be equal to 0.15. ... 2.24x10-5 d 0.15 upon calculations a 3.36 X106M It equilibrium, _[hg 43 = * = 3.36x10-6M) comect option is . Scanned with CamScanner