mean = 40 and sd = 12
a)
P(35 <X < 45)
= P((35 - 40)/(12/sqrt(9)) < z < (45 - 40)/(12/sqrt(9)))
= P(-1.25 < z < 1.25)
= 0.7887
b)
P(X > 50)
= P( z > (50 - 40)/(12/sqrt(9)))
= P(z > 0.9938)
= 0.0062
c)
Given CI Level = 95%
Margin of Error(ME) = 4
std. dev. = 12
z-value of 95% CI = 1.9600
n = (z*sigma/ME)^2
n = (1.96*12/4)^2
= 35
8. A paint line can completely paint a produce with a mean time of 40 minutes...
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i please get help with this!!
Suppose a geyser has a mean time between eruptions of 96 mins.
let the interval of time between the eruptions be normally
distributed with standard deviation 19 mins. complete parts a thru
e
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