1)Because the pressure is the highest at the bottom and probably the thickness of the levee was independent of depth.
2)Mass=rho*pi*r^2*h=7870*pi*0.01425^2*0.858=4.31 kg.
Clearly a cart is not needed.
3)Density of sun=mass/volume=1.99*10^30/(4.3*pi*(6.96*10^8)^3)=436.93kg/m^3
4)Gauge pressure=rho*g*h=1000*9.81*3200Pa=3.139*10^7Pa=309.8 atm
5)Gauge pressure at interface=rho1*g*h1=600*9.81*0.12=706.3Pa
Gauge pressure at bottom=rho1*g*h1+rho2*g*h2=600*9.81*0.12+1000*9.81*0.25=3158.8Pa
6)Pressure=F/A=1.5/(pi*0.0041^2)=28404Pa
h=P/rho*g=28404/(1000*9.81)=2.90m
7)Buoyancy=17.5-11.2=6.3N
Volume of water=buoyant force/(rho*g)=6.3/(1000*9.8)=6.43*10^-4m^3
Density=Mass/volume=(weight/g)/(volume)=(17.5/9.81*6.43*10^-4)=2774kg/m^3
8)Buoyant force=39.2-28.4=10.8N
Volume=10.8/(9.81*1000)=1.101*10^-3m^3
Buoyant force in other liquid=39.2-18.6=20.6N
Density=buoyant force/(g*volume)=20.6/(9.81*1.101*10^-3)=1907kg/m^3
Lecture 2 Examples: Density, Pressure and Buoyancy During the Great Mississippi Flood of 1993, the level...
Question 8 solution
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