(A) impedance = sqrt(40^2 + 29^2) = 49.4 ohm
(B) POwer factor = R / Z = 0.725
(C) Irms = Vrms / Z = 460 / 49.4 = 9.31 A
(d) R / Z = 1
R= z
Xc= 40 ohm
40 = 1 / (2 x pi x 60 x C)
C =66.3 x 10^-6 F = 66.3 uF
(e) P = V I
2.51 x 10^3 =460 I
I = 5.46 A
Problem 24.57 Part A Manufacturing Plant Power A manufacturing plant uses 2.51 kW of electric power...
Problem #1: A 25 KW motor with lagging power factor of 0.75 in a manufacturing plant is running from a 240V, 60 Hz. power line. The utility company is going to impose penalty on their utility bill unless they improve their power factor to 0.9 (lagging). Determine: a) The current reactive power(Q) and the improved Q of the motor b) The size of the capacitor needed for the correction of the power factor.
Part A A mill in a textile plant uses the belt-and-pulley arrangement shown to transmit power. When t = 0 an electric motor is turning pulley A with an angular velocity of wa=5 rad/s. (Figure 1) If this pulley is subjected to a constant counterclockwise angular acceleration of a = 2 rad/s., determine the angular velocity of pulley B after B turns 3 revolutions. The hub at D is rigidly connected to pulley C and turns with it. Express your...
Need help on part D & E
Problem 2: Pedal Power
Many villages in the developing world lack access to electricity.
One proposed solution is the ‘Free Electric’ bicycle, which is a
stationary bike hooked up to a generator and battery. Pedaling the
bike powers the generator, which creates electricity that is stored
in the battery. The inventor claims that 1 hour on the bike can
produce a whole day of electricity. Let’s put it to the test!
Assume the...