G = G° + RT*lnKc
G° = -32.8
RT = 8.314*298
Kp = CH4^2 / (C2H6)(H2)
Kp = 0.7^2 / (0.45*0.45) = 2.41975
dn = 2 -1-1 = 0
Kp = Kc*(RT)^dn
Kp = Kc
then
G = G° + RT*lnKc
G= -32800 + 8.314*298*ln(2.41975) = -30610.6 J
G = -30.610 kJ/mol
stion 13 of 14 aping learning For a reaction, standard conditions are 298 K and a...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N (8) + 3H2(g) + 2NH3(g) the standard change in Gibbs free energy is AGⓇ = -72.6 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PN, = 0.200 atm, PH, = 0.450 atm, and PNH, = 0.750 atm? AG= L kJ/mol AG= kJ/mol
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For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 bar for all species. For the reaction N2(g) + 3 H2(g) = 2 NH3(g) the standard change in Gibbs free energy is AGⓇ = -72.6 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PN, = 0.200 bar, Ph, = 0.150 bar, and PnHz = 0.800 bar. kJ AG = mol
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For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction N2(g) + 3H2(g) + 2NH3(g) the standard change in Gibbs free energy is AG° –72.6 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are Pin, 0.150 atm, PH, = 0.200 atm, and PNH, 0.850 atm? = = =
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For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. the reaction 328 kJmol. What is AG for this reaction at 298 K when Pw, the standard change in Gibbs free energy is AG the partial pressures are 0.650 and Po, = 0.300 atm atm, r,o=0.150 atm, Number AG25.5 kJ/ mol
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