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10.2.22 : Question Help The data show the bug chirps per minute at different temperatures. Find the regression equation, lett

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  • The following data are passed: Bug chirps per minute Temperature (°F) 1240 95.2 1195 85.5 928 77.5 809 67.8 932 72.5 763 66.7Based on the above table, the following is calculated: 8 = 3x3 = 5867 – 97.83333333 = 3Y, 465,2 = 7.523333333 586x = x - : (E​​​​​​
  • The regression equation is

y` = 24.59 + (0.0541) x

  • Predicted Temperature when bug chirping = 3000

y` = 24.59 + (0.0541) × (3000)

y` = 186.89

above predicted value is outside of the interval of Temperature average values.

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