You need to be able to read an integer, which is a string of decimal digits, possibly beginning with a ‘-’ sign. Ignoring the possible minus sign, the classic algorithm for converting a string of digits into a number is based on initializing an accumulator value to 0. Then for each digit of the input, multiply the accumulator by ten and add in the value (0-9) of the digit.
C++ code:-
#include <bits/stdc++.h>
using namespace std;
int main()
{
char choice;
do
{
cout << "\n Enter an integer : ";
string str;
cin>>str;
int i,n;
double acc = 0;
if(str[0] == '-')
{
for(i = 1 ; i <
str.length() ; i++ )
acc = acc*10 + (str[i]-'0');
}
else
{
for(i = 0 ; i <
str.length() ; i++ )
acc = acc*10 + (str[i]-'0');
}
cout<<"\n Converted Integer : "<<acc<<endl;
cout<<"\n Press y to continue . n To
exit : ";
cin>>choice;
}while(choice != 'n');
return 0;
}
--------------------------------------------------------------------------------------------------------------------------------
Output :-

You need to be able to read an integer, which is a string of decimal digits,...
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import java.util.*;
public class PairFinder {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
// Read in the value of k
int k = Integer.parseInt(sc.nextLine());
// Read in the list of numbers
int[] numbers;
String input = sc.nextLine();
if (input.equals("")) {
numbers = new int[0];
} else {
String[] numberStrings = input.split(" ");
numbers = new int[numberStrings.length];
for (int i = 0; i < numberStrings.length; i++) {
numbers[i] = Integer.parseInt(numberStrings[i]);
}
}
System.out.println(findPairs(numbers, k));
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