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254 Chapter 6 Multiphane Sysicoms Percentage Saturation (Percentage Humidity) -n) × 100% ที่ (P-pp at a given temperature and pressure, you fraction of the vapor solve the defining equation to cakulate the partial peessure or mo ia the gas; thercafter, degrees of superheat. quantities for a gas If you are given amy of these q to given previously to calculate the dew point and you can use the formulas 3. The vapor pressure of styreae is 100 mm Hg at 82°C and 200 mm Hg at 100°C. A gas that contained in a tank at İOPC TEST YOURSELF consistso (Answers, p 68) and 1000 mm Hg Caleulate: of 10 mole% styrene and 90 mole % noncondensable, is L. The dew point of the gas 2. The relative saturation. &. The molal saturation and percentage saturation. CREATIVITY EXERCISES L. Suppose you know the temperature and barometric pressure on a given day. List as many ways as you can think of to determine-exactly or approximately-the mole fraction of water vapor in the air Gas rea 2. Repeat question 1, only this time limit yourself to methods in which a stuffed bear plays a part in the determination. (Example: Saturate the bear with water, and measure the rate at which it loses weight due to evaporation.) Encyclopedia bsorber ter Humid air at 75.C 1.1 bar, and 30% relative humidity is fed into a process unit at a rate of 1000 nh. Determine (1) the molar fow rates of water, dry air, and oxygen entering the process unit, (2) the molal hamidity, abnolute humidity, and percentage humidity of the air, and (3) the dew point stripper rul the re SOLUTION C) upor-Liquid I 5)259mm He (from Table B.3) Pio (0.3)0289 mm Hg) 86 7 mm Hg 5+273-3 P-1.1 bar825 mm Hg o (867 mm Hg) (825 mm Hg)0.105 mol HOmol The molar flow rate of wet air is given by the ideal gas equation of state as 6.4- RT 1000 m kmol 38.0 kmol 010 kmol HO kmol H20 3.99 kmol 38.0 kmol (1-0105) kmol BDA kmol BDA 34.0 kmol 34.0 kmol BDA 021 kmol O 7.14 kmol BDA
ateo The same resalt coald have heen obeained from the reslits of part 1s 0,07% ke 11,00 0.539 COMPONENT GAS-LIQUID SYSTEMS Gas-liquid processes reactions distillation, and transfer of one or more species from a gas to a liquid (absorption or crubblagh or vice versa (stripping) that involve several components in each phase include many chemical Whcs multicomponent gas and liquid phases are in equilibrium, a limited number of in- given by the Gibbs phase teeive system variables may be specified arbitrarily (the number is rule 1, and the remaining variables can then he dstribution of components between the two phases In this section we define several such be determined using equilibrium relationships for relasioeships and ilfustrate how they are used in the solution of material balance problems liqpid Equilibrium Data The best way to evaluate equilibrium compositions is from tabulated data. Perrys Chemical nginers Handbook (see footnote 1). pp. 2-76 through 2-89, gives partial pressures of vapors over various liquid solutions Example 6.4-L illustrates the use of such data. borption of SO Je stream consisting of 100 lbmleh of an sor air mature containing 45 toes so, is con- ted with lquid water in a continuous absorber at 30°C. The liquid leaving the absorber is analvzed d found to contain 200 g of SO, per 100 g of H,O. Assuming that the gas and liquid streams leav hed in the water and the required water feed rate. ing the absorber are in equilibrium at 30°C and 1 atm, calculate the fraction of the ent Rals Gieen Feed Rate of Gas

Can someone explain me ..how they got the 29.o kg bda pls
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