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4. Addressing modes (10 pts) There are many ways to get the address for the operands...
Anyone explain to (i), (ii) How can we get the instruction words and R8=?[hex]? (i) instruction...
Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
How can I get that?
Consider the following instructions given in the table below. For each instruction determine its length (in words), the instruction words (in hexadecimal), source operand addressing mode, and the content of register R7 after execution of each instruction. Fill in the empty...
Stack Operation 10. (10 pts.) Show the contents of the stack and affected registers at the two marked points in the exe...
Stack Operation 10. (10 pts.) Show the contents of the stack and affected registers at the two marked points in the execution of the followin code. Assume RO-0, R1-1, R2-2, R3-3, R4-4, R5-5, and R6-6. The initial value for stack pointer (prior to executing this code block) is given as SP-0x20001000 PUSH R2,R3) ADD R4, R1, Re ;<---A POP R5, R6) ADD R5, R5, R4 ADD R6, R6, R5 PUSH (R4-R6); SUBS Re, RO,R1-B a) Show the contents of Stack,...
Problem 5 (15pts): Describe what the following program is doing (Do not need to explain each line of instruction....
Problem 5 (15pts): Describe what the following program is doing (Do not need to explain each line of instruction. Just show me the purpose of this code). .equ LEDS, Ox100000 10 # define LEDS Ox10000010 .text global start #base address of LEDS on DEO-Nano start: movia r2, LEDS movi r3, 0b00000001 movi r4, OX7FFF slli r4, r4, 3 add r4, r4, r4 load: movi r5, 0b10000000 loop: stw rs, o(r2) mov r6, ro count: addi r6, r6, 1 bne r6,...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218 Ox021C 40 Ox0302 Ox0301 Ox0300 30 20 D1 D2 D3 D4 D5 D6 D7 D8 10 The following MSP430 memory system consists of 2 consecutive 64-Byte RAM chips starting at location ox200, and 512 Byte of Flash ending at 0XFFFF. Fill in the blanks (4) with the correct starting or ending addresses. C Starting Address Starting Address Ending Address (Binary) (Hex) (Hex) 64B RAM1...
The AVR provides a rich instruction set to support high-level languages. The AVR address- ing modes...
The AVR provides a rich instruction set to support high-level languages. The AVR address- ing modes also simplify the access of complex data structures. The AVR has a version of the ADD instruction that includes the C flag as one of the source operands, which enables multiple- precision addition operation. The AVR also has a version of the SUB instruction that includes the C flag as one of source operands and hence is used to perform multiprecision subtraction operation. The...
Consider a VEX-executing VLIW machine with the following characteristics: The machine supports 4 slots (4-wide machine)...
Consider a VEX-executing VLIW machine with the following characteristics: The machine supports 4 slots (4-wide machine) with the following resources: 2 memory units each with a load latency of 3 cycles 2 integer-add/sub functional units with a latency of 2 cycle 1 integer-multiply functional unit with a latency of 4 cycles Each functional unit in the machine is pipelined and can be issued a new operation at each cycle. However, the results of an operation are only available after the...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which ar...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which are located in memory from address 0 through 15. Show the result of the MIPS instruction "lw Ss0,4(Sa0)" for machines in little-endian byte orders, where Sa0 4. Address Contents Address Contents 9b lb 2 4 6 10 b4 c5 12 13 14 15 3d 5f 70 7 8f (b) (10pts)Assume we have the following time, performance and architecture parameters in the specified units Ec-...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which are located in memory from address 0 through 15. Show the result of the MIPS instruction "lw Ss0,4(Sa0)" for machines in little-endian byte orders, where Sa0 4. Address Contents Address Contents 9b lb 2 4 6 10 b4 c5 12 13 14 15 3d 5f 70 7 8f (b) (10pts)Assume we have the following time, performance and architecture parameters in the specified units Ec-...
Question 29 3 pts MIPS branch instructions compute their destination by subtracting the branch address from...
Question 29 3 pts MIPS branch instructions compute their destination by subtracting the branch address from PC 4 True False Question 31 3 pts PC-relative addressing cau cover (access) the whole memory space of MIPS. True False Question 32 2 pts If the current vlue of the PC is Ox00000000. you can use a single jump instruetion to get to the PC address as Ox00100400. True False Question 35 2 pts What is the comrect value for? in the following...
Part 2 (22 pts) .ORIG x3000 LEA R1, STRZ AND R2, R2, #0 LD R4, CHAR...
Part 2 (22 pts) .ORIG x3000 LEA R1, STRZ AND R2, R2, #0 LD R4, CHAR REPEAT LDR R3, R1, #0 BRz FINISH ;Branch to FINISH if the value of R3 is zero ADD R3, R3, R4 BRnp PASS ;Branch to PASS if the value of R3 is positive or negative ADD R2, R2, #1 PASS ADD R1, R1, #1 BR REPEAT ;Branch always to REPEAT FINISH ST R2, COUNT HALT CHAR .FILL xFF91 COUNT .FILL x0000 STRZ .STRINGZ "Hello...
Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
How can I get that?
Consider the following instructions given in the table below. For each instruction determine its length (in words), the instruction words (in hexadecimal), source operand addressing mode, and the content of register R7 after execution of each instruction. Fill in the empty...
Stack Operation 10. (10 pts.) Show the contents of the stack and affected registers at the two marked points in the execution of the followin code. Assume RO-0, R1-1, R2-2, R3-3, R4-4, R5-5, and R6-6. The initial value for stack pointer (prior to executing this code block) is given as SP-0x20001000 PUSH R2,R3) ADD R4, R1, Re ;<---A POP R5, R6) ADD R5, R5, R4 ADD R6, R6, R5 PUSH (R4-R6); SUBS Re, RO,R1-B a) Show the contents of Stack,...
Problem 5 (15pts): Describe what the following program is doing (Do not need to explain each line of instruction. Just show me the purpose of this code). .equ LEDS, Ox100000 10 # define LEDS Ox10000010 .text global start #base address of LEDS on DEO-Nano start: movia r2, LEDS movi r3, 0b00000001 movi r4, OX7FFF slli r4, r4, 3 add r4, r4, r4 load: movi r5, 0b10000000 loop: stw rs, o(r2) mov r6, ro count: addi r6, r6, 1 bne r6,...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218 Ox021C 40 Ox0302 Ox0301 Ox0300 30 20 D1 D2 D3 D4 D5 D6 D7 D8 10 The following MSP430 memory system consists of 2 consecutive 64-Byte RAM chips starting at location ox200, and 512 Byte of Flash ending at 0XFFFF. Fill in the blanks (4) with the correct starting or ending addresses. C Starting Address Starting Address Ending Address (Binary) (Hex) (Hex) 64B RAM1...
The AVR provides a rich instruction set to support high-level languages. The AVR address- ing modes also simplify the access of complex data structures. The AVR has a version of the ADD instruction that includes the C flag as one of the source operands, which enables multiple- precision addition operation. The AVR also has a version of the SUB instruction that includes the C flag as one of source operands and hence is used to perform multiprecision subtraction operation. The...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which are located in memory from address 0 through 15. Show the result of the MIPS instruction "lw Ss0,4(Sa0)" for machines in little-endian byte orders, where Sa0 4. Address Contents Address Contents 9b lb 2 4 6 10 b4 c5 12 13 14 15 3d 5f 70 7 8f (b) (10pts)Assume we have the following time, performance and architecture parameters in the specified units Ec-...
Problem 4 (15pts): (a) (5pts) Consider the following MIPS memory with data shown in hex, which are located in memory from address 0 through 15. Show the result of the MIPS instruction "lw Ss0,4(Sa0)" for machines in little-endian byte orders, where Sa0 4. Address Contents Address Contents 9b lb 2 4 6 10 b4 c5 12 13 14 15 3d 5f 70 7 8f (b) (10pts)Assume we have the following time, performance and architecture parameters in the specified units Ec-...
Question 29 3 pts MIPS branch instructions compute their destination by subtracting the branch address from PC 4 True False Question 31 3 pts PC-relative addressing cau cover (access) the whole memory space of MIPS. True False Question 32 2 pts If the current vlue of the PC is Ox00000000. you can use a single jump instruetion to get to the PC address as Ox00100400. True False Question 35 2 pts What is the comrect value for? in the following...
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