Homework Answers
a)
P(have symptom A)=P(have disease D1 and symptom A)+P(have disease D2 and symptom A)
=0.06*0.4+0.02*0.8=0.04
b)P(Carries D1 given have symptom A)==P(have disease D1 and symptom A)/P(have symptom A)
=0.06*0.4/0.04=0.6
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I want the solution for this.
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