Question

3. A 1.29 kg ball is connected by means of two ideal strings to a horizontal, rotating rod. The strings are tied to the rod and are taut. The right string is 26.0 cm long and has a tension of 29.3 N, and it makes an angle 02 = 50.0° with the rod, while the left string makes an angle 01 = 64.0° angle with the rod. At the instant shown the ball is at its highest point. (a) What is the tension in the left-hand string? 4. (b) What is the speed of the ball? m/s

Answer 1

ay Ties on Tiego, a o BC тX Y X Т Tz EgO2 y = sie O2 r=Bex Sin Oz & Tzsinda = 268 Sin 50° *T, sino = 19.gem. = .199 m. Tz Cg O2 = T, ego, 29.3 x Cos So' = Tix egs 64° T. - 29.3 x esso - 42.96 N Cg64" : Tension in the left hand string is 42.9617

b) Now centripetal force Tisiot Tz Ein Qt ng will provide so . Tisi Q t Iz Sin ating = muza P(T, sio t Izlid ting) m m .199(42.96 sin64°+29.3 Sin 50° + 1.29X9-8) 1.29 V = 3.37 mis. speed of the ball is 3.37 m/s.