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1. Calculate the molarity a solution prepared by adding 14.0 g of sodium sulfate to enough water to make 250.00 mL. 1.182 M O
Taking Pool 6 1. What volume of 0.250 M HCl is required to react with 0.500 moles of calcium hydroxide? 2.00 L 0.500 L 0.250
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Answer #1

1) molarity = (W /MW) (1000 / V in mL)

molarity = (14.0 / 142) (1000 / 250)

molarity = 0.394 M

answer = option 5 = 0.394 M

2) Ca(OH)2 + 2HCl ---------> CaCl2 + 2H2O

1 mole Ca(OH)2 reacts with 2 moles HCl

0.500 moles Ca(OH)2 reacts with 0.500 x 2 = 1.0 moles HCl

M = n /V

V = M / n = 0.250 / 1.0

V = 1.0 L

answer = option 4 = 1.0 L

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