Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing...

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Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing...

Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing building with only a 13 m space between them. What is the angular distance, in degrees, of the radio wave after it emerges from between the buildings?

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Answer 1

Answer #1

thetamin = arcsine (wavelength / width of slit)
= arcsine (speed of light / (frequency * width of slit) )

= sin^(-1)(3*10^8/(800*10^6 * 13))

= sin^(-1)(0.0289)

= 1.653⁰

That is the angle between the central max and the first minimum

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Answer 2

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Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing...

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