If the coefficient of kinetic friction between a 33.0 kg crate and the floor is 0.360,...
If the coefficient of kinetic friction between a 33.0 kg crate and the floor is 0.360, what horizontal force is required to move the crate at a steady speed across the floor?
Homework Answers
from the newton second law
net force = ma
here crate is moving with a constant speed so acceleration is zero
net force = 0
F-fk = 0
F = fk = muek*n
n = normal force = mg
F = 0.36*33*9.8 = 116.4 N
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