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4. Determine the slope and deflection at end point C of the cantilever beam shown in the figure. Use E = 200 GPa, I = 10 x 10

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Jerm- 3 kN/m X 2 KNM B MA 2m al E = 200 GPA I= 107 mme RA х EI= 2000 kNm² Reactions [EFU =) RA 3X2 RA = 6 KN EMA right -MA +My = Rax - My Xo = 3¢ 1 + 3 (2-2)2 My = 6x – 48° - 32 Box! + 3(2-2) So, EI dy dy2 6x - 4x - 3012 +3 12-22 2 © Integrating botAt x=0; y 20. ot (2 (2=0 Now; slope at e; from Ega ; At X=4 ; dy Oc da 3 EI/dy) dae 3 (9 – (9) - ° + (2) 2 2 ) EI OC 4 Oc 4 2Doubts and Queries are welcomed in the comment box! Thank you !

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