Question

Consider the following hypotheses: Check my work Ho! HS 570 HA: > 570 Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or table) a. I = 576; s = 21; n = 27 0.01 s p-value < 0.025 0.025 s p-value < 0.05 Op-value 20.10 p-value <0.01 0.05 s p-value <0.10 b. x=576; s = 21; n = 54 p-value < 0.01 0.01 s p-value < 0.025 0.025 s p-value < 0.05 0.05 s p-value <0.10 D-value 2010 < Prey 2 of 5 Next > SA 7 ORO

Answer 1

Ho: ME 570 HA: M > 570 (a) ă=576 ,s=21, n=27 then use It stand and deviation is unknown use t-test. If standard deviation is konown then 2-test According because to problem we usef-test given s=21 and stand and Ý unknown. deviation t = sin 576-570 - sto 21/527 = 1.48 5.20 = degree of freedom is nola 29-1 e 26

- P=0.0748 >0.05 So, Answer is: 10.ossp-value collol 6 civeu; X=576,8=21, n=54 t = ă Mo - sisu 576-570 21/554 = 201 degree of freedom n-1= 54-1 = 53 p=0.0203 <0.05 Answere. is: [0.01<p-value <0.025 l

© Given z = 576,5=12, n=15 t = ato = 576-570 s su 12/515 12/3TS -1.936 degree of freedom = n-1 = 151 =14 P-value = 0.036 so Answer is : 10.025 <p value <0.05) (d) Criven, x=573, n=15, 5=12 t X - Mo -577-570 sisu 121515 = 3 = 0.968 121555 edom -n-1= 151=14 P-value = orange 0.1747 Aswere: P-value > 0.10