Question

Design the circuit in Fig. P.5 to establish Ic = 0.5(mA) and Vc= 0.5(V). Assume VBE = 0.65(V) at Ic = 0.1(mA), and 3 = 200. T

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+2v sel Rc ove RE -2V Given Ic 0.5mA Ve= 0.55 AS 2 Ic Re -0.5 2-0.5= (0.5) x1013 RC 115 Rc 0.5x103 Rea 3x103 R Re= 3k0As given in question, Vibe = 0-65V Ic = 0.1mA B = 200 I c = 6 Ig AS VB=0 0.65 VB-VE Ve= -0.65 V AS, VE - TE RE +2 = 0 VE +2 =RE 270 RON) (0.1*103) RE - 1.343 x 104 RE= 13.43K2 hot In order to prevent the BJT from entering very deeply into satweation,So, Re=17.5 Kn Thus Re should be Rc=17.5kr for BIT not to enter deep saturation,

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