Question

Question Completion Status: QUESTION 10 2 points Save Answer John is the manager at a fast food restaurant and would like to determine the average number of cars waiting for their order in the drive-through line during his hours of operation. Every day at noontime, he counts the number of cars in the drive-through. Because of the lunchtime traffic, his survey overestimates the actual average throughout the day. This error is due to O sampling error O nonsampling error nonprobability error. periodicity. QUESTION 11 2 points Save Answer In November 2011, 14.8% of visitors to the Travelocity website hailed from the Google search engine. A random sample of 160 visitors on the Travelocity was selected. The standard error of the proportion is 0.0519 0.0135 0.0633 0.0281

Answer 1

10. Since the owner is considering the the time period at the lunch time only which doesnt't truly

reflects the population so the error is

Sampling error

11.

We are given

Probablity, P = 14.8% = 0.148

n = sample size = 160

Standard error proportion(SE) = SQRT{ P(1-P) / n }

SQRT = square root

= SQRT{ 0.148(0.852) / 160 }

= 0.0281

0.0281