Question

Problem 4.38 Part A The load in (Figure 1) of 2490 lb is to be supported by the two vertical steel wires for which oy = 68 ksi. Originally wire AB is 60 in. long and wire AC is 60.04 in. long. Each wire has a cross-sectional area of 0.02 in2. Est = 29.0(103) ksi. Determine the force developed in wire AB after the load is suspended. Express your answer to three significant figures and include appropriate units. TAB = Value Units Submit Request Answer Figure < 1 of 1 > Part B Determine the force developed in wire AC after the load is suspended. Express your answer to three significant figures and include appropriate units. 160.04 in. ? 60 in. DI HÅR Tac = Value O 2 Units Submit Request Answer

Answer 1

let tension in cable AB= TAB tension in cable . AL=TAC total load TAB + TAL=2490 lb Orial displacement = or PL AE for barlwire A B , P=TAB L=60 in E=29x103 Ksi A=0.02 in?

A=0.02 in? DAB=AAC for Barlwire AL ,P=TAL L=60.04 in E=29000 ksi both bar/wire are attached with load TABX60 a TAC 860.04 0.02X29000 0.02 X29000 TAB = 1501 TAL TABI TAL = 2490 Ub 500

150) 1500 TAC & TAC = 2490 lb TAC = 1244.58 ub TAB= 1245:42 Mb

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