Let f(n) = n^2 +200 Let g(n) = 200 n Select the first answer below that...

Question

Question

engineering Computer-Science

Answer 1

Answer #1

Ω (g(n)) = {f(n): there exist positive constants c and
n0 such that 0 <= cg(n) <= f(n) for
all n >= n0}.
f(n)=n^2+200
g(n)=200*n

for value of n>=199
f(n)>=cg(n)

So f is Ω(g)

Thanks a lot

Answer 2

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