Question

Regular C Programming

DESCRIPTION To make telephone numbers easier to remember, some companies use letters to show their telephone number, but mapping the letters to the numbers on a standard telephone keypad: 1 2 ABC 3 DE 4G 5 11 6 MNO 7 PONS 8 Tu 9.xyz # For example, using letters & spaces, the telephone number 438-5626 can be shown as GET LOAN. In some cases, to make a telephone number meaningful, companies might use more than seven letters. For example, 225-5466 can be displayed as CALL HOME,which uses eight letters. Write a program that prompts the user to enter a telephone number expressed in letters/spaces and outputs the corresponding telephone number in digits. if the user enters more than seven letters, then process only the first seven letters. Also output the - (hyphen) after the third digit.

It is just a random generator of telephone numbers

Answer 1

HI,
code :

#include<stdio.h>
#include<stdlib.h>
#include<time.h> // to use time
#include<string.h> // to use strcmp
void mapAndPrint(char * number){
int i=0;
while(number[i] != '\0'){
if(strchr("abc",tolower(number[i])) != NULL){
printf("%d",2);
}else if(strchr("def",tolower(number[i])) != NULL){
printf("%d",3);
}else if(strchr("ghi",tolower(number[i])) != NULL){
printf("%d",4);
}else if(strchr("jkl",tolower(number[i])) != NULL){
printf("%d",5);
}else if(strchr("mno",tolower(number[i])) != NULL){
printf("%d",6);
}else if(strchr("pqrs",tolower(number[i])) != NULL){
printf("%d",7);
}else if(strchr("tuv",tolower(number[i])) != NULL){
printf("%d",8);
}else if(strchr("wxyz",tolower(number[i])) != NULL){
printf("%d",9);
}
if(i == 2){
printf("-");
}
i++;
}
printf("\n");
}
char* getNumber(char * number, char * parsed){
int i=0,j=0;
while(number[i] != '\0' && j<7){
if(isalpha(number[i]) != 0){
parsed[j] = number[i];
j++;
}
i++;
}
}
// retuns random number in between lower and higher values
int getRandomInRange(int lower, int higher){
return (rand() % (higher - lower + 1)) + lower;;
}
// prints phone number length of 8 including -
void printPhoneNumber(){
// printf("%s\n",number);
for(int i=0;i<8;i++){
if(i!=3){ // if index not 3 then print random number
printf("%d", getRandomInRange(0,9));
}else{
printf("-"); // if index 4 print -
}
  
}
printf("\n");
}
int main()
{
int n;

srand(time(0)); // set the seed random number
printf("Enter telephone number using letterss (EXIT to quit) :"); // ask user enter firsttime
char userneed[25];
// int i=0;
// char c;
// while(i<7){
// scanf("%c",&c);
// if(isalpha(c) != 0){
// userneed[i] = c;
// i++;   
// }
// }
// printf("entered-->%s\n",userneed);
gets(userneed); // get the string
char parsedNumber[8];
getNumber(userneed, parsedNumber);
printf("parsed-->%s",parsedNumber);
while(strcmp(parsedNumber,"EXIT") != 0){ // upto not exit
printf("Correspomding telephone number is :\n");
mapAndPrint(parsedNumber); // printing phone number
printf("Enter telephone number using letterss (EXIT to quit) :");
gets(userneed);
getNumber(userneed, parsedNumber);
}
return 0;
}

Output:
1)

Enter telephone number using letterss (EXIT to quit) : GET LOAN Correspomding telephone number is : 438-5626 Enter telephone number using letterss (EXIT to quit) Call Home Correspomding telephone number is : 225-5466 Enter telephone number using letterss (EXIT to quit) : EXIT

EXPLANATION:

As we don't have any information about user requirements we are just generating random number for any query of user.

To get random number in between range use formula,
( rand() % (higher - lower + 1) )+ lower // here % reminder operator.

Note : strcpy returns 0 if both strings are same.

Hope you got your answer. Please comment below if any queries.

Enter telephone number using letterss (EXIT to quit) :GET LOAN Corresponding telephone number is : 151-4643 Enter telephone number using letterss (EXIT to quit) : HOEM LOAN Correspomding telephone number is : 746-3744 Enter telephone number using letterss (EXIT to quit) :EXIT