Question

How to ues Python dictionary, enter the student information and get the following classification.

The student id is "key" and the subject name and grade is "value" to form the following form.

04차시 실습3을 활용하여, 학생의 학번을 key로, 학과, 이름, 과제성적 을 value로 하는 딕셔너리 구성 >> 학생 정보 딕셔너리 (학번 학과 이름 과제성적 을 띄어 쓰기로 입력할 것) | 1번째 학생의 정보를 입력하세요 : 2019310000 0 0 학과 김 0 50 2번째 학생의 정보를 입력하세요: 2016310000 0 0 학과 이미미 60 13번째 학생의 정보를 입력하세요 : 2017310000 aa 학과 박00 70 14번째 학생의 정보를 입력하세요: 2014310000 bb학과 천 0 0 40 15번째 학생의 정보를 입력하세요: 2018310000 cc 학과 연 0 0 70 | 2019310000 [ㅁㅁ 학과', '김 ㅇㅇ', '50'] | 2016310000 ['00 학과', '이미', '60] print(">> 학생 정보 딕셔너리 <<) | 2017310000 ['aa학과', '박 ㅇㅇ', '70'] print('(학번 학과 이름 과제성적 을 띄어 쓰기로 입력할 것)') | 2014310000 ['bb학과', '천 0 0', '40'] student={} | 2018310000 [cc학과', '연 00', '70] for i in range(1,6): a=input("%d번째 학생의 정보를 입력하세요: '%i).split() #a[0]을 key로 하고, a[1]을 value로 하는 쌍 추가 for stu in student | print(stu, student[stu])

This is my code, I don't know how to use the dictionary..

student_list = []
a = input("Student information 1: ")
b = input("Student information 2: ")

student_list.append(a[])
student_list.append(b)

print(student_list)

print(" {}".format([a] + [b]));

Answer 1

Program :

#dictionary for storing student details
#dictionary is of the form "key" : "value"
#here key is student id
#here value is subject, name and grade

student_dict = {}

#read the number of students
#whose data is to be entered
num_of_students = int(input("Enter the number of students : "))

#read the students data
#number_of_students + 1 is used, because range() start from 1
for i in range(1,num_of_students + 1):

a = input("Student information %d : "%i).split()
  
#here data is read in the form
# 2018000 CS peter 70
# it is split into a list as
# a = [2018000,CS,Peter,70]
#here key is a[0] , i.e., 2018000
#here value is a[1:] , i.e., [CS,Peter,70]
# a[1:] returns a list from index 1 to the end

#enter the split data to dictionary
#student["key"] = value
student_dict[a[0]] = a[1:]

#display the values in student dictionary
#in the form key [ value ]

for stu in student_dict:

print(stu,student_dict[stu])

  

Output :

ryPython.py Enter the number of students : 4 Student information 1 : 2018000 CS Peter 70 Student information 2 : 2019000 CS Alan 88 Student information 3 : 2019004 CS Akash 78 Student information 4 : 2019410 cS Karthi 67 2018000 ['CS', 'Peter, '70'] 2019000 ['CS', 'Alan', '88'] 2019004 ['CS', 'Akash', '78'] 2019410 ['CS', 'Karthi', '67'] >>>

Source code screenshot :

File Edit Format Run Options Window Help S #dictionary for storing student details #dictionary is of the form "key" : "value" #here key is student id #here value is subject, name and grade student dict = {} #read the number of students #whose data is to be entered th num of students int (input ("Enter the number of students : ") ) #read the students data #number of students + 1 is used, because range () start from 1 for i in range (1, num of students + 1): input ("Student information %d : "%i).split() #here data is read in the form # 2018000 Cs peter 70 # it is split into a list as [2018000, CS, Peter, 70] #here key is a[0] , i.e., 2018000 #here value is a[1:] , i.e., [CS, Peter, 70] # a[1:] returns a list from index 1 to the end #enter the split data to dictionary #student ["key"] student dict[a[0]] = a[1:] = value Не a #display the values in student dictionary Lic #in the form key [ value ] 16/ 70 for stu in student dict: 88 print (stu, student dict [stu]) Ln: 35 C