Question

30. Suppose a researcher is interested in the effectiveness of a new novel talk therapy technique in reducing overall depression as identified via score report on the geriatric depression scale (GDS). In order to carry out this hypothesis, the researcher gathers a SRS of participants in the program and performs the GDS test prior to, and after initiation of the new therapy technique. Assume the SRS score report presented below represents an approximately normal distribution. Participant GDS Score (Out of 15 GDS Score (Out of 15)

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Answer 1

A) The type of study design is pre/post test B) Null and alternative Hypothesis GDS Score prier GDS Score following d-x-y (d - d(d - d) 0.8333 0.6944 1.3612 0.0278 0.0278 0.0278 0.8333 0.6944 2.8333 to intervention (X) to intervention 4 12 13 12 14 1.1667 0.1667 0.1667 0.1667 9 4 Total 29 d=2= 29-4.8333 6 T= n-1 | 2.8333-vo·56666-0.7528 6-1 4.83334.8333 15.727 S/Vn 0.7528/V6 0.30733

P-value-0.000 The p-value of Paired t-test is 0.000. This is less than 0.05. Thus, Reject Ho that the new talk therapy results in the same score on the depression index. c) The 95% confidence interval representing the average difference in score on the GDS is, 0.7%2非 d ± !em = 4.8333 ± 2.571 *a -4.8333 +2.571*0.30733 4.8333 ± 0.79015 = (4.04315, 5.62345) d±t* (4.043, 5.623) (Rounded to three decimal places) Thus the 95% confidence interval representing the average difference in score on the GDS is (4.043, 5.623). The 0 is no within the interval, which would indicate a significant result.