Question

I am wondering on the very last part of this problem how they got the answer given

part a only

10-3-17 HW 4.27 Secco 100% 3902300 pd .489 - 495 0923 Goose Coob General Higher order transfer To Se tuin ga OLELL Le Steady Sor ( L=T= ce vi plin • Kuh.02

Answer 1

If you like my work please upvote ? for any doubts comment below for clarification

* Quecally second oder ein af form G(S) = 0 - a la __ $+2ę wons. A important 9(6)= 0.02 for understands 5 +0.025 +0.0005 - 0 Given aqwns. Wor W = 0.0005 Woo 0 092 4. Tachon of une 0.02 T Tachov = 100 sec EWA = 0.01 Ç= 0.4989 < So under damped. Ta gwa 0-100 By @ K= 100 sec; time scalling ley 100 we get t= 1 sec; ire, Tv- op @ 03100. property : - scaling of division (o) in time donain (G) is multiplication in frequency domain so I - w X100) So wat teem = (100) multiplied . çon team = 100 multiplied. from 0 4 obseave clearly and apply above. 5+2.02 (100)s+0.0005(101) = 572015 200 104 (0.02), 969) =