Answer:
R code:
grow <- c(7,3)
total<- c(7,9)
prop.test(grow, total, conf.level = 0.95,correct = FALSE)
R output:
>grow <- c(7,3)
> total<- c(7,9)
> prop.test(grow, total, conf.level = 0.95,correct = FALSE)
2-sample test for equality of proportions without continuity
correction
data: grow out of total
X-squared = 7.4667, df = 1, p-value = 0.006285
alternative hypothesis: two.sided
95 percent confidence interval:
0.3586880 0.9746453
sample estimates:
prop 1 prop 2
1.0000000 0.3333333
Calculated chi square = 7.4667, P=0.0063 which is < 0.05 level of significance.
Ho is rejected.
We conclude that cell line survival rate is different between those two cell lines.
please use R and show input and output. Any data that is needed is provided in...
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pasted a section in the article. Thank you!!
Figure 6. MLL5 Suppresses Differentiation of GBM
Self-Renewing Cells
(A) Western blot to assess the effects of MLL5 knockdown in the
GBM primary culture G432NS.
(B) Western blots on cell lysates from two GBM cultures
differentiated over a 21-day period.
(C) Heatmap and unsupervised hierarchical clustering of
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Please explain figures 6C, 6D, 6F, and 6G in simple
terms! I am having difficulty understanding the figures. I have
copy and pasted a section in the article. Thank you!!
Figure 6. MLL5 Suppresses Differentiation of GBM
Self-Renewing Cells
(A) Western blot to assess the effects of MLL5 knockdown in the
GBM primary culture G432NS.
(B) Western blots on cell lysates from two GBM cultures
differentiated over a 21-day period.
(C) Heatmap and unsupervised hierarchical clustering of
differentially regulated genes...
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