Question

Question 18 (10 April 2020) 51.5 kW 12 cm Pump An oil pump is drawing 51.5 kW of electric power while pumping oil with p= 860 kg/m3 at a rate of 0.23 m3/s. The inlet and outlet diameters of the piper are 8 cm and 12 cm, respectively. If the pressure rise of oil in the pump is measured to be 500 kPa and the motor efficiency is 87.5 percent, determine the mechanical efficiency of the pump. Motor 8 cm Oil AP = 500 kPa 23 ml

Answer 1

yoz Morou power (Pm): 6105 aw , Yw=0-875" • Swayt powes (Ps): 3105x0•875 = 45°06WW. 77 worden op = 4*0000 = 45076 mlo ofron 15 let alin - 4*0.93.2 - 90831 mfB அடி பே அடி pang mata - pag * Hm uma XCO Hms: manometric e P.-P2 + ro / Hm: pg 29 +8, 212 - -500XLOR + 43076-30847 860x9081 2 x 9.81 t has 2647 m .. Hydraulic power Pot = pg quomi WC - Pn= 860x9.81x0o23 x 26.4 1000 I Ph= 51.23 xw You deck daka sir 2 35 Give u pos} Thank you ® Efficiency can't be greater than to there must be some eroor in data if we nequcz 'motor effo (Yua) they for 5035 = 99.50. 7 Amp (Thank you 51023 : 99.54.