m1 = 80 kg
L = 6 m
d = 2 m
m2 = 3000 kg
Part A )
the net torque here is zero
TA d - m1 g L/2 - m2 g x = 0
TA = ( m1L/2 + m2 x ) (g/d )
x vlaue missing remaining all values are avilable
plug in the values and finalise TA
Part B )
TA - TB - m1 g - m2 g = 0
TB = TA - m1 g - m2 g
from above TA, m1, m2 and g values
finalise TB value.
Part A Find TA, the tension in string A. The figure (Figure 1) shows a model...
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Find the magnitude of tension in the two cords shown in the figure
(Figure 1) .
A) Neglect the mass of the cords, and assume
that the angle ? is 39 degrees and the mass m is
160 kg . What is the magnitude of the tension in the right
cord?
Express your answer using two significant figures and use the
following answer format: Fin right cord =______ N
B) What is the
magnitude of the tension in the left...